Hi Everyone,
I am trying to hide a column in a matrix table. I have no
trouble using conditional formatting to control the visibility of the
column, but when I hide the column the main row in the matrix does not
shrink. Therefore, I have a big gap... My thought was to use conditional
formatting to control the column width of the main matrix row. Listed
below is the expression that I used. Can anyone help me with the error
message or recommend a better solution?
=IIF(Fields!FiscalYear.Value = IIF(Month(TODAY()) = 10-12,Year(TODAY()) ,Year(Today())-1), 0.625in, 0.25in) cannot be
parsed as a unit because it does not contain numeric values. Examples
of valid unit strings are "1pt" and ".5in".
Regards,
A.AkinPut double quotes around the "0.625in" and "0.25in"
"awakin" wrote:
> Hi Everyone,
>
> I am trying to hide a column in a matrix table. I have no
> trouble using conditional formatting to control the visibility of the
> column, but when I hide the column the main row in the matrix does not
> shrink. Therefore, I have a big gap... My thought was to use conditional
> formatting to control the column width of the main matrix row. Listed
> below is the expression that I used. Can anyone help me with the error
> message or recommend a better solution?
>
>
>
> =IIF(Fields!FiscalYear.Value = IIF(Month(TODAY()) => 10-12,Year(TODAY()) ,Year(Today())-1), 0.625in, 0.25in) cannot be
> parsed as a unit because it does not contain numeric values. Examples
> of valid unit strings are "1pt" and ".5in".
>
> Regards,
>
> A.Akin
>|||That doesn't help. It still gives the same error message.
Is there another way of doing this?
"Michael C" wrote:
> Put double quotes around the "0.625in" and "0.25in"
>
> "awakin" wrote:
> > Hi Everyone,
> >
> >
> >
> > I am trying to hide a column in a matrix table. I have no
> > trouble using conditional formatting to control the visibility of the
> > column, but when I hide the column the main row in the matrix does not
> > shrink. Therefore, I have a big gap... My thought was to use conditional
> > formatting to control the column width of the main matrix row. Listed
> > below is the expression that I used. Can anyone help me with the error
> > message or recommend a better solution?
> >
> >
> >
> >
> >
> >
> >
> > =IIF(Fields!FiscalYear.Value = IIF(Month(TODAY()) => > 10-12,Year(TODAY()) ,Year(Today())-1), 0.625in, 0.25in) cannot be
> > parsed as a unit because it does not contain numeric values. Examples
> > of valid unit strings are "1pt" and ".5in".
> >
> >
> >
> > Regards,
> >
> >
> >
> > A.Akin
> >
> >|||Anthoney,
Did you ever figure this out? I need to control the width of a column but
it appears column width isn't formattable via an expression.
thanks,
Justin
"AnthonyG" wrote:
> That doesn't help. It still gives the same error message.
> Is there another way of doing this?
> "Michael C" wrote:
> >
> > Put double quotes around the "0.625in" and "0.25in"
> >
> >
> > "awakin" wrote:
> >
> > > Hi Everyone,
> > >
> > >
> > >
> > > I am trying to hide a column in a matrix table. I have no
> > > trouble using conditional formatting to control the visibility of the
> > > column, but when I hide the column the main row in the matrix does not
> > > shrink. Therefore, I have a big gap... My thought was to use conditional
> > > formatting to control the column width of the main matrix row. Listed
> > > below is the expression that I used. Can anyone help me with the error
> > > message or recommend a better solution?
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > > =IIF(Fields!FiscalYear.Value = IIF(Month(TODAY()) => > > 10-12,Year(TODAY()) ,Year(Today())-1), 0.625in, 0.25in) cannot be
> > > parsed as a unit because it does not contain numeric values. Examples
> > > of valid unit strings are "1pt" and ".5in".
> > >
> > >
> > >
> > > Regards,
> > >
> > >
> > >
> > > A.Akin
> > >
> > >
Friday, February 24, 2012
Conditional Column Formatting
Labels:
column,
conditional,
control,
database,
formatting,
hide,
matrix,
microsoft,
mysql,
oracle,
server,
sql,
table,
trouble,
visibility
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